When I reference a photo link in a info = statement. such as
http://www.myhomeautophotos.com/photos/17/17878/17878_10011TB5_1.JPG
I get an XML Parsing Error because the link sees the "_" characters as <strong> and then </strong> as shown below.
http://www.myhomeautophotos.com/photos/17/17878/17878<strong>10011TB5</strong>1.JPG
I am not a php programmer, what can I do??

